2y^2-8=28

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Solution for 2y^2-8=28 equation:


Simplifying
2y2 + -8 = 28

Reorder the terms:
-8 + 2y2 = 28

Solving
-8 + 2y2 = 28

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 2y2 = 28 + 8

Combine like terms: -8 + 8 = 0
0 + 2y2 = 28 + 8
2y2 = 28 + 8

Combine like terms: 28 + 8 = 36
2y2 = 36

Divide each side by '2'.
y2 = 18

Simplifying
y2 = 18

Take the square root of each side:
y = {-4.242640687, 4.242640687}

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